What is the Relationship Between the Chord of a Circle and a Perpendicular to it from the Center? We just need to apply the chord length formula: Chord length = 2√(r 2-d 2), where 'r' is the radius of the circle and 'd' is the perpendicular distance from the center of the circle to the chord. If the radius and the distance of the center of the circle to the chord are given, the chord of the circle can be calculated.
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How to Find the Length of Chord of Circle with a Given Radius? It is the line that passes through the center of a circle touching two points on the circumference. The longest chord of a circle is its diameter.
When the radius and the distance from the center of the circle to the chord is given, we need to apply the chord length formula: Chord length = 2√(r 2-d 2) where 'r' is the radius of the circle and 'd' is the perpendicular distance from the center of the circle to the chord.The length of the chord of a circle can be calculated according to the given dimensions, with the help of two methods. How to Find the Chord of Circle?Īny line segment whose endpoints are on the circumference of the circle is the chord of that circle. The longest chord in a circle is its diameter which passes through its center. The chord of a circle refers to a straight line joining two points on the circumference of the circle. The diameter is the longest chord of a circle.įAQs on Chord of a Circle What is the Chord of a Circle in Mathematics?.When two radii join the two ends of a chord, they form an isosceles triangle.The radius of a circle bisects the chord at 90°.If we draw multiple chords in a circle starting from the diameter to both the ends, we will observe that as we move closer to the center, the chord increases in length. Theorem 3: For two unequal chords of a circle, the larger chord will be closer to the center than the smaller chord. Observe the following circle to understand the theorem in which chord AB = chord CD, and they are equidistant from the center if PO = OQ. Theorem 2: Chords of a circle, equidistant from the center of the circle are equal. Observe the following circle to understand the theorem in which OP is the perpendicular bisector of chord AB and the chord gets bisected into AP and PB. Theorem 1: The perpendicular to a chord, drawn from the center of the circle, bisects the chord. With two additional iterations the error is smaller than the precision of a double float.The chord of a circle has a few theorems related to it. With using this for $\theta$ we get $r\approx 5.004$ in only three iterations. Then $x_1\approx 2.02$ according to the formula above. But you get the point.ĮDIT: Of course, instead of bisection we might also use Newton: So we are somewhat off, mainly because we calculated $\theta$ only with a precision of $3/4\pi-1/2\pi = \pi/4$, which is kind of large. We could continue this way to improve this value, but let’s go with $\theta = m = 5/8\pi$. This is a function that is falling montonously for $0\leq \theta \leq 2\pi$, so while we cannot invert this exactly we can easily invert this numerically, for example by simple bisection: To get this independent of $r$ lets consider If you have radius $r$ and angle $\theta$ in rad, then $A = r\theta$ and $C = 2r\sin(\theta/2)$.